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Chap 4- 1 Chapter 4 Basic Probability Business Statistics: A First Course 6 th

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Chap 4-Copyright ©2013 Pearson Education, Inc. publishing as Prentice Hall Learning ObjectivesIn this chapter, you learn: Basic probability conceptsConditional probability To use Bayes’ theorem to revise probabilitiesVarious counting rules

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Слайд 1Chap 4-
Chapter 4

Basic Probability
Business Statistics: A First Course 6th Edition

Chap 4-Chapter 4Basic ProbabilityBusiness Statistics: A First Course 6th Edition

Слайд 2Chap 4-
Copyright ©2013 Pearson Education, Inc. publishing as Prentice Hall



Learning Objectives
In this chapter, you learn:

Basic probability concepts
Conditional probability


To use Bayes’ theorem to revise probabilities
Various counting rules
Chap 4-Copyright ©2013 Pearson Education, Inc. publishing as Prentice Hall Learning ObjectivesIn this chapter, you learn: Basic

Слайд 3Chap 4-
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Basic Probability Concepts
Probability – the chance that an uncertain event

will occur (always between 0 and 1)

Impossible Event – an event that has no chance of occurring (probability = 0)

Certain Event – an event that is sure to occur (probability = 1)

Chap 4-Copyright ©2013 Pearson Education, Inc. publishing as Prentice Hall Basic Probability ConceptsProbability – the chance that

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Assessing Probability
There are three approaches to assessing the probability of

an uncertain event:
1. a priori -- based on prior knowledge of the process


2. empirical probability -- based on observed data


3. subjective probability

based on a combination of an individual’s past experience, personal opinion, and analysis of a particular situation

Assuming all outcomes are equally likely

probability of occurrence

probability of occurrence

Chap 4-Copyright ©2013 Pearson Education, Inc. publishing as Prentice Hall Assessing ProbabilityThere are three approaches to assessing

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Example of a priori probability
When randomly selecting a day from

the year 2012 what is the probability the day is in January?
Chap 4-Copyright ©2013 Pearson Education, Inc. publishing as Prentice Hall Example of a priori probabilityWhen randomly selecting

Слайд 6Business Statistics: A First Course.
Chap 4-
Example of a priori probability
Find

the probability of selecting a face card (Jack, Queen, or

King) from a standard deck of 52 cards.
Business Statistics: A First Course.Chap 4-Example of a priori probabilityFind the probability of selecting a face card

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Example of empirical probability
Find the probability of selecting a male

taking statistics from the population described in the following table:

Probability of male taking stats

Chap 4-Copyright ©2013 Pearson Education, Inc. publishing as Prentice Hall Example of empirical probabilityFind the probability of

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Events
Each possible outcome of a variable is an event.

Simple event
An

event described by a single characteristic
e.g., A day in January from all days in 2012
Joint event
An event described by two or more characteristics
e.g. A day in January that is also a Wednesday from all days in 2012
Complement of an event A (denoted A’)
All events that are not part of event A
e.g., All days from 2012 that are not in January
Chap 4-Copyright ©2013 Pearson Education, Inc. publishing as Prentice Hall EventsEach possible outcome of a variable is

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Sample Space
The Sample Space is the collection of all

possible events
e.g. All 6 faces of a die:


e.g. All 52 cards of a bridge deck:
Chap 4-Copyright ©2013 Pearson Education, Inc. publishing as Prentice Hall Sample SpaceThe Sample Space is the collection

Слайд 10All 52 cards of a bridge deck
Chap 4-

All 52 cards of a bridge deckChap 4-

Слайд 11Chap 4-
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Visualizing Events
Contingency Tables -- For All Days in 2012



Decision Trees
All

Days
In 2012

Not Jan.

Jan.

Not Wed.

Wed.

Wed.

Not Wed.

Sample Space

Total
Number
Of
Sample
Space
Outcomes

4
27
48
287

Chap 4-Copyright ©2013 Pearson Education, Inc. publishing as Prentice Hall Visualizing EventsContingency Tables -- For All Days

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Chap 4-
Visualizing Events
Contingency Tables



Decision

Trees
Red 2

24 26

Black 2 24 26

Total 4 48 52

Ace Not Ace Total

Full Deck
of 52 Cards

Red Card

Black Card

Not an Ace

Ace

Ace

Not an Ace

Sample Space

Sample Space

2
24
2
24

Business Statistics: A First Course.Chap 4-Visualizing Events Contingency Tables Decision Trees Red

Слайд 13Business Statistics: A First Course.
Chap 4-
Visualizing Events
Venn Diagrams
Let A

= aces
Let B = red cards




A
B
A ∩ B = ace

and red

A U B = ace or red

Business Statistics: A First Course.Chap 4-Visualizing EventsVenn Diagrams Let A = acesLet B = red cardsABA ∩

Слайд 14Chap 4-
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Definition: Simple Probability
Simple Probability refers to the probability of a

simple event.
ex. P(Jan.)
ex. P(Wed.)

P(Jan.) = 31 / 366

P(Wed.) = 52 / 366

Not Wed. 27 287 314

Wed. 4 48 52

Total 31 335 366

Jan. Not Jan. Total

Chap 4-Copyright ©2013 Pearson Education, Inc. publishing as Prentice Hall Definition: Simple ProbabilitySimple Probability refers to the

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Definition: Joint Probability
Joint Probability refers to the probability of an

occurrence of two or more events (joint event).
ex. P(Jan. and Wed.)
ex. P(Not Jan. and Not Wed.)

P(Jan. and Wed.) = 4 / 366

P(Not Jan. and Not Wed.)
= 287 / 365

Not Wed. 27 287 314

Wed. 4 48 52

Total 31 335 366

Jan. Not Jan. Total

Chap 4-Copyright ©2013 Pearson Education, Inc. publishing as Prentice Hall Definition: Joint ProbabilityJoint Probability refers to the

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Mutually Exclusive Events
Mutually exclusive events
Events that cannot occur simultaneously

Example: Randomly

choosing a day from 2010

A = day in January; B = day in February

Events A and B are mutually exclusive
Chap 4-Copyright ©2013 Pearson Education, Inc. publishing as Prentice Hall Mutually Exclusive EventsMutually exclusive eventsEvents that cannot

Слайд 17Business Statistics: A First Course.
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Mutually Exclusive Events

Example: Drawing

one card from a deck of cards

A = queen

of diamonds; B = queen of clubs

Events A and B are mutually exclusive
Business Statistics: A First Course.Chap 4-Mutually Exclusive Events Example: Drawing one card from a deck of cards

Слайд 18Chap 4-
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Collectively Exhaustive Events
Collectively exhaustive events
One of the events must occur


The set of events covers the entire sample space

Example: Randomly choose a day from 2012

A = Weekday; B = Weekend;
C = January; D = Spring;

Events A, B, C and D are collectively exhaustive (but not mutually exclusive – a weekday can be in January or in Spring)
Events A and B are collectively exhaustive and also mutually exclusive
Chap 4-Copyright ©2013 Pearson Education, Inc. publishing as Prentice Hall Collectively Exhaustive EventsCollectively exhaustive eventsOne of the

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Chap 4-
Collectively Exhaustive Events




Example:
A

= aces; B = black cards;
C = diamonds; D

= hearts

Events A, B, C and D are collectively exhaustive (but not mutually exclusive – an ace may also be a heart)
Events B, C and D are collectively exhaustive and also mutually exclusive
Business Statistics: A First Course.Chap 4- Collectively Exhaustive Events Example: 			A = aces; B = black cards;

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Computing Joint and Marginal Probabilities
The probability of a joint event,

A and B:



Computing a marginal (or simple) probability:


Where B1, B2, …, Bk are k mutually exclusive and collectively exhaustive events
Chap 4-Copyright ©2013 Pearson Education, Inc. publishing as Prentice Hall Computing Joint and  Marginal ProbabilitiesThe probability

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Joint Probability Example
P(Jan. and Wed.)

Chap 4-Copyright ©2013 Pearson Education, Inc. publishing as Prentice Hall Joint Probability ExampleP(Jan. and Wed.)

Слайд 22Business Statistics: A First Course.
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Joint Probability Example
P(Red and Ace)
Black
Color
Type
Red
Total
Ace
2
2
4
Non-Ace
24
24
48
Total
26
26
52

Business Statistics: A First Course.Chap 4-Joint Probability ExampleP(Red and Ace)BlackColorTypeRedTotalAce224Non-Ace242448Total262652

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Marginal Probability Example
P(Wed.)

Chap 4-Copyright ©2013 Pearson Education, Inc. publishing as Prentice Hall Marginal Probability ExampleP(Wed.)

Слайд 24Business Statistics: A First Course.
Chap 4-
Marginal Probability Example
P(Ace)
Black
Color
Type
Red
Total
Ace
2
2
4
Non-Ace
24
24
48
Total
26
26
52

Business Statistics: A First Course.Chap 4-Marginal Probability ExampleP(Ace)BlackColorTypeRedTotalAce224Non-Ace242448Total262652

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P(A1 and B2)
P(A1)
Total
Event
Marginal & Joint Probabilities

In A Contingency Table

P(A2 and B1)

P(A1 and B1)

Event

Total

1

Joint Probabilities

Marginal (Simple) Probabilities

A1

A2

B1

B2

P(B1)

P(B2)

P(A2 and B2)

P(A2)

Chap 4-Copyright ©2013 Pearson Education, Inc. publishing as Prentice Hall     P(A1 and B2)P(A1)TotalEventMarginal

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Probability Summary So Far
Probability is the numerical measure of the

likelihood that an event will occur
The probability of any event must be between 0 and 1, inclusively

The sum of the probabilities of all mutually exclusive and collectively exhaustive events is 1

Certain

Impossible

0.5

1

0

0 ≤ P(A) ≤ 1 For any event A

If A, B, and C are mutually exclusive and collectively exhaustive

Chap 4-Copyright ©2013 Pearson Education, Inc. publishing as Prentice Hall Probability Summary So FarProbability is the numerical

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General Addition Rule
P(A or B) = P(A) + P(B) -

P(A and B)

General Addition Rule:

If A and B are mutually exclusive, then
P(A and B) = 0, so the rule can be simplified:

P(A or B) = P(A) + P(B)
For mutually exclusive events A and B

Chap 4-Copyright ©2013 Pearson Education, Inc. publishing as Prentice Hall General Addition RuleP(A or B) = P(A)

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General Addition Rule Example
P(Jan. or Wed.) = P(Jan.) + P(Wed.)

- P(Jan. and Wed.)

= 31/366 + 52/366 - 4/366 = 79/366

Don’t count the four Wednesdays in January twice!

Chap 4-Copyright ©2013 Pearson Education, Inc. publishing as Prentice Hall General Addition Rule ExampleP(Jan. or Wed.) =

Слайд 29Marble Example 1: A bag contains 4 white, 3 red,

2 black, 2 green, 1 yellow, and 0 blue marbles.

One marble is chosen at random. Determine the probability of each event.
1. P(green)=
2. P(blue)=
3. P (not white)=
4. P (red or black)=

General Addition Rule Example

Marble Example 1: A bag contains 4 white, 3 red, 2 black, 2 green, 1 yellow, and

Слайд 30Card Example: One card is randomly chosen from a standard

deck of 52 cards. Determine the probability of each event.


1. P(king)= 2. P(heart)=
3. P (face card)= 4. P (not a spade)=
5. P(king and heart)= 6. P(king or heart)=
7. P(10 and jack)= 8. P(10 or jack)=
9. P (diamond or face card)=
10. P (red card or queen)=

General Addition Rule Example

Card Example: One card is randomly chosen from a standard deck of 52 cards. Determine the probability

Слайд 31Chap 4-
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Computing Conditional Probabilities
A conditional probability is the probability of one

event, given that another event has occurred:

Where P(A and B) = joint probability of A and B
P(A) = marginal or simple probability of A
P(B) = marginal or simple probability of B

The conditional probability of A given that B has occurred

The conditional probability of B given that A has occurred

Chap 4-Copyright ©2013 Pearson Education, Inc. publishing as Prentice Hall Computing Conditional ProbabilitiesA conditional probability is the

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What is the probability that a car has a GPS

given that it has AC ?

i.e., we want to find P(GPS | AC)

Conditional Probability Example

Of the cars on a used car lot, 90% have air conditioning (AC) and 40% have a GPS. 35% of the cars have both.

Chap 4-Copyright ©2013 Pearson Education, Inc. publishing as Prentice Hall What is the probability that a car

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Conditional Probability Example
Of the cars on a used car lot,

90% have air conditioning (AC) and 40% have a GPS.
35% of the cars have both.

(continued)

Chap 4-Copyright ©2013 Pearson Education, Inc. publishing as Prentice Hall Conditional Probability ExampleOf the cars on a

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Conditional Probability Example
Given AC, we only consider the top row

(90% of the cars). Of these, 35% have a GPS. 35% of 90% is about 38.89%.

(continued)

No GPS

GPS

Total

AC

0.35

0.55

0.90

No AC

0.05

0.05

0.10

Total

0.40

0.60

1.00

Chap 4-Copyright ©2013 Pearson Education, Inc. publishing as Prentice Hall Conditional Probability ExampleGiven AC, we only consider

Слайд 35Business Statistics: A First Course, 5e © 2009 Prentice-Hall, Inc.
Chap

4-
What is the probability that a car has a CD

player, given that it has AC ?

i.e., we want to find P(CD | AC)

Conditional Probability Example

Of the cars on a used car lot, 70% have air conditioning (AC) and 40% have a CD player (CD). 20% of the cars have both.

Business Statistics: A First Course, 5e © 2009 Prentice-Hall, Inc.Chap 4-What is the probability that a car

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Using Decision Trees
Has AC
Does not have AC
Has GPS
Does not have

GPS

Has GPS

Does not have GPS

P(AC)= 0.9

P(AC’)= 0.1

P(AC and GPS) = 0.35

P(AC and GPS’) = 0.55

P(AC’ and GPS’) = 0.05

P(AC’ and GPS) = 0.05

All
Cars

Given AC or no AC:

Conditional
Probabilities

Chap 4-Copyright ©2013 Pearson Education, Inc. publishing as Prentice Hall Using Decision TreesHas ACDoes not have ACHas

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Using Decision Trees
Has GPS
Does not have GPS
Has AC
Does not have

AC

Has AC

Does not have AC

P(GPS)= 0.4

P(GPS’)= 0.6

P(GPS and AC) = 0.35

P(GPS and AC’) = 0.05

P(GPS’ and AC’) = 0.05

P(GPS’ and AC) = 0.55

All
Cars

Given GPS or no GPS:

(continued)

Conditional
Probabilities

Chap 4-Copyright ©2013 Pearson Education, Inc. publishing as Prentice Hall Using Decision TreesHas GPSDoes not have GPSHas

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Independence
Two events are independent if and only if:



Events A and

B are independent when the probability of one event is not affected by the fact that the other event has occurred
Chap 4-Copyright ©2013 Pearson Education, Inc. publishing as Prentice Hall IndependenceTwo events are independent if and only

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Multiplication Rules
Multiplication rule for two events A and B:
Note: If

A and B are independent, then

and the multiplication rule simplifies to

Chap 4-Copyright ©2013 Pearson Education, Inc. publishing as Prentice Hall Multiplication RulesMultiplication rule for two events A

Слайд 40Multiplication Rules
Marble Example 2: A bag contains 4 white,

3 red, 2 black, 2 green, 1 yellow, and 0

blue marbles. One marble is chosen at random. It is replaced, and then another marble is randomly chosen. Determine the probability of each event.
1. P(green is chosen first and red is chosen second)=
2. P(black is chosen first and black is chosen second)=
3. P (green and red in either order)=
Multiplication Rules Marble Example 2: A bag contains 4 white, 3 red, 2 black, 2 green, 1

Слайд 41Multiplication Rules
Marble Example 3: A bag contains 4 white,

3 red, 2 black, 2 green, 1 yellow, and 0

blue marbles. One marble is chosen at random. It is not replaced, and then another marble is randomly chosen. Determine the probability of each event.
1. P(green is chosen first and red is chosen second)=
2. P(black is chosen first, and black is chosen second)=
Multiplication Rules Marble Example 3: A bag contains 4 white, 3 red, 2 black, 2 green, 1

Слайд 42Chap 4-
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Marginal Probability
Marginal probability for event A:





Where B1, B2, …, Bk

are k mutually exclusive and collectively exhaustive events
Chap 4-Copyright ©2013 Pearson Education, Inc. publishing as Prentice Hall Marginal ProbabilityMarginal probability for event A:Where B1,

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Bayes’ Theorem
Bayes’ Theorem is used to revise previously calculated probabilities

based on new information.

Developed by Thomas Bayes in the 18th Century.

It is an extension of conditional probability.
Chap 4-Copyright ©2013 Pearson Education, Inc. publishing as Prentice Hall Bayes’ TheoremBayes’ Theorem is used to revise

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Bayes’ Theorem
where:
Bi = ith event of k mutually exclusive and

collectively
exhaustive events
A = new event that might impact P(Bi)
Chap 4-Copyright ©2013 Pearson Education, Inc. publishing as Prentice Hall Bayes’ Theoremwhere:		Bi = ith event of k

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Bayes’ Theorem Example
A drilling company has estimated a 40% chance

of striking oil for their new well.
A detailed test has been scheduled for more information. Historically, 60% of successful wells have had detailed tests, and 20% of unsuccessful wells have had detailed tests.
Given that this well has been scheduled for a detailed test, what is the probability
that the well will be successful?
Chap 4-Copyright ©2013 Pearson Education, Inc. publishing as Prentice Hall Bayes’ Theorem ExampleA drilling company has estimated

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Let S = successful well
U = unsuccessful

well
P(S) = 0.4 , P(U) = 0.6 (prior probabilities)
Define the detailed test event as D
Conditional probabilities:
P(D|S) = 0.6 P(D|U) = 0.2
Goal is to find P(S|D)

Bayes’ Theorem Example

(continued)

Chap 4-Copyright ©2013 Pearson Education, Inc. publishing as Prentice Hall Let  S = successful well

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Bayes’ Theorem Example
(continued)
Apply Bayes’ Theorem:
So the revised probability of success,

given that this well has been scheduled for a detailed test, is 0.667
Chap 4-Copyright ©2013 Pearson Education, Inc. publishing as Prentice Hall Bayes’ Theorem Example(continued)Apply Bayes’ Theorem:So the revised

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Given the detailed test, the revised probability of a successful

well has risen to 0.667 from the original estimate of 0.4

Bayes’ Theorem Example

Sum = 0.36

(continued)

Chap 4-Copyright ©2013 Pearson Education, Inc. publishing as Prentice Hall Given the detailed test, the revised probability

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Counting Rules
Rules for counting the number of possible outcomes

Counting Rule

1:
If any one of k different mutually exclusive and collectively exhaustive events can occur on each of n trials, the number of possible outcomes is equal to


Example
If you roll a fair die 3 times then there are 63 = 216 possible outcomes

kn

Chap 4-Copyright ©2013 Pearson Education, Inc. publishing as Prentice Hall Counting RulesRules for counting the number of

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Counting Rules
Counting Rule 2:
If there are k1 events on the

first trial, k2 events on the second trial, … and kn events on the nth trial, the number of possible outcomes is


Example:
You want to go to a park, eat at a restaurant, and see a movie. There are 3 parks, 4 restaurants, and 6 movie choices. How many different possible combinations are there?
Answer: (3)(4)(6) = 72 different possibilities

(k1)(k2)…(kn)

(continued)

Chap 4-Copyright ©2013 Pearson Education, Inc. publishing as Prentice Hall Counting RulesCounting Rule 2:If there are k1

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Counting Rules
Counting Rule 3:
The number of ways that n items

can be arranged in order is


Example:
You have five books to put on a bookshelf. How many different ways can these books be placed on the shelf?

Answer: 5! = (5)(4)(3)(2)(1) = 120 different possibilities

n! = (n)(n – 1)…(1)

(continued)

Chap 4-Copyright ©2013 Pearson Education, Inc. publishing as Prentice Hall Counting RulesCounting Rule 3:The number of ways

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Counting Rules
Counting Rule 4:
Permutations: The number of ways of arranging

X objects selected from n objects in order is



Example:
You have five books and are going to put three on a bookshelf. How many different ways can the books be ordered on the bookshelf?

Answer: different possibilities

(continued)

Chap 4-Copyright ©2013 Pearson Education, Inc. publishing as Prentice Hall Counting RulesCounting Rule 4:Permutations: The number of

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Counting Rules
Counting Rule 5:
Combinations: The number of ways of selecting

X objects from n objects, irrespective of order, is



Example:
You have five books and are going to randomly select three to read. How many different combinations of books might you select?

Answer: different possibilities

(continued)

Chap 4-Copyright ©2013 Pearson Education, Inc. publishing as Prentice Hall Counting RulesCounting Rule 5:Combinations: The number of

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Chapter Summary
Discussed basic probability concepts
Sample spaces and events, contingency tables,

simple probability, and joint probability
Examined basic probability rules
General addition rule, addition rule for mutually exclusive events, rule for collectively exhaustive events
Defined conditional probability
Statistical independence, marginal probability, decision trees, and the multiplication rule
Discussed Bayes’ theorem
Discussed various counting rules
Chap 4-Copyright ©2013 Pearson Education, Inc. publishing as Prentice Hall Chapter SummaryDiscussed basic probability conceptsSample spaces and

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