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Today’s ObjectivesDefinition of an arithmetic progression and the nth termSum of an arithmetic progression

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Слайд 103 Series

03 Series

Слайд 2Today’s Objectives
Definition of an arithmetic progression and the nth term
Sum

of an arithmetic progression

Today’s ObjectivesDefinition of an arithmetic progression and the nth termSum of an arithmetic progression

Слайд 3Arithmetic Progressions (APs)
An arithmetic progression is when the difference between

each term is a fixed real amount.
This difference is

known as the common difference and we use the letter d.
Two examples of arithmetic progressions are;
6, 10, 14, 18, … (Tn = 6 + (n – 1)4)
and –2, –6, –10, –14, … (Tn = –2 + (n – 1)(–4))
Arithmetic Progressions (APs)An arithmetic progression is when the difference between each term is a fixed real amount.

Слайд 4Arithmetic Progressions (APs)
So the general formula for the nth term

of an arithmetic progression is:

Tn = a +

(n – 1)d

where a is the first term and d is the common difference.
Arithmetic Progressions (APs)So the general formula for the nth term of an arithmetic progression is: Tn =

Слайд 5AP Example 1
The 8th term of an AP is 11

and the 15th term is 21. What is the common

difference and the nth term?

To answer this we will use the formula for the nth term, Tn = a + (n – 1)d, to find the common difference d and the first term a.
AP Example 1The 8th term of an AP is 11 and the 15th term is 21. What

Слайд 6AP Example 1
Solution:

AP Example 1Solution:

Слайд 7AP Example 2
The nth term of an AP is 12

– 4n. What is the 1st term and the common

difference?

To find the 1st term we will use the nth term when n = 1. To find the common difference we will find the 2nd term when n = 2 and subtract the 1st term from the 2nd term (since T1 + d = T2).
AP Example 2The nth term of an AP is 12 – 4n. What is the 1st term

Слайд 8AP Example 2
Solution:

AP Example 2Solution:

Слайд 9AP Example 3
An AP with all positive terms, is such

that T1T10 = 12 and T1/T10 = 1/3.
i) Find

the common difference,
ii) Find the value of the next term after the 10th term which is a whole number.

i) To find the common difference we will use the nth term , Tn = a + (n – 1)d, to form simultaneous equations and solve for a and d.
ii) We must choose a value of n (n>10) to resolve any fractions in Tn.
AP Example 3An AP with all positive terms, is such that T1T10 = 12 and T1/T10 =

Слайд 10AP Example 3
i) Solution:
All terms are positive so d >

AP Example 3i) Solution:All terms are positive so d > 0.

Слайд 11AP Example 3
ii) Solution:
Tn is a whole number. So, n

– 1 is a multiple of 9.
From part i) above:

AP Example 3ii) Solution:Tn is a whole number. So, n – 1 is a multiple of 9.From

Слайд 12Sum of an AP
Considering the sum of the first n

terms of the sequence (i.e. the series), where a is

the first term, d is the common difference and l is the last term:


But this is rather long.
Sum of an APConsidering the sum of the first n terms of the sequence (i.e. the series),

Слайд 13Sum of an AP
So now consider the same expression backwards

and add the two together:





Considering the RHS there are

n terms. So we can simplify the RHS:
Sum of an APSo now consider the same expression backwards and add the two together: Considering the

Слайд 14Sum of an AP
Simplified we have:


Hence the sum of

the n terms of an arithmetic progression is given by:

Sum of an APSimplified we have: Hence the sum of the n terms of an arithmetic progression

Слайд 15Sum of an AP
Also, since the last term, l, can

be written as: a + (n – 1)d, we can

replace l in the above formula to get an alternative formula for the sum of n terms of an AP.
Sum of an APAlso, since the last term, l, can be written as: a + (n –

Слайд 16Sum of an AP Example 1
Evaluate



Rather than calculating all of

the terms, we will see that this is an AP

and so we can use the formula for the sum of an AP.
Sum of an AP Example 1EvaluateRather than calculating all of the terms, we will see that this

Слайд 17Sum of an AP Example 1
Solution:
Consider the first few terms:



This

is an AP where n = 8, a = 4/3

and d = –2/3
Therefore,
Sum of an AP Example 1Solution:Consider the first few terms:This is an AP where n = 8,

Слайд 18Sum of an AP Example 2
In an AP the sum

of the first 10 terms is 50 and the 5th

term is three times the 2nd term. Find the 1st term and the sum of the first 20 terms.

We will find the 1st term by solving simultaneous equations. This will also give us the common difference and we can then find the sum of the first 20 terms using the formula for Sn.
Sum of an AP Example 2In an AP the sum of the first 10 terms is 50

Слайд 19Sum of an AP Example 2
Solution:

Sum of an AP Example 2Solution:

Слайд 20Sum of an AP Example 3
Show that the terms of

the following series are in arithmetic progression:


Then find the sum

of the first 10 terms.
Sum of an AP Example 3Show that the terms of the following series are in arithmetic progression:Then

Слайд 21Sum of an AP Example 3
Solution:
To show the terms are

in arithmetic progression, we must show that there is a

common difference.
Sum of an AP Example 3Solution:To show the terms are in arithmetic progression, we must show that

Слайд 22Sum of an AP Example 3
There is a common difference

of ln2 and so the series is in arithmetic progression.

a

= ln2 and d = ln2. So the sum of the first 10 terms is:
Sum of an AP Example 3There is a common difference of ln2 and so the series is

Слайд 23Sum of an AP Example 4
The sum of the first

n terms of a sequence is given by n(n +

3). Find the fourth term of the sequence and show that the terms are in arithmetic progression.

Since we have the formula for the sum, then the sum of the first four terms subtract the sum of the first three terms will give us the fourth term itself. To show that the series is in arithmetic progression, we must show that the difference between a general term and the next term is a constant.




Sum of an AP Example 4The sum of the first n terms of a sequence is given

Слайд 24Sum of an AP Example 4
Solution: Finding the fourth term:

Sum of an AP Example 4Solution: Finding the fourth term:

Слайд 25Sum of an AP Example 4
Solution: Show series is an

AP:








Since an and an–1 are general terms then this holds

for all n. Since the difference between two general terms is a constant then this means the series is an AP.
Sum of an AP Example 4Solution: Show series is an AP:Since an and an–1 are general terms

Слайд 26Sum of an AP Example 5
Find the least number of

terms of the AP 1 + 3 + 5 +

… that are required to make a sum exceeding 2000.

We need to establish the first term and the common difference to solve the resulting inequality in n, Sn > 2000.




Sum of an AP Example 5Find the least number of terms of the AP 1 + 3

Слайд 27Sum of an AP Example 5
Solution:

Sum of an AP Example 5Solution:

Слайд 28Sum of an AP Example 6
Find three numbers in AP

whose sum is 15 and whose product is 80.

We need

to consider three general terms in AP and then form simultaneous equations using their sum and their product.




Sum of an AP Example 6Find three numbers in AP whose sum is 15 and whose product

Слайд 29Sum of an AP Example 6
Solution:
Let the three general terms

in AP be a, a + d and a +

2d:
Sum of an AP Example 6Solution:Let the three general terms in AP be a, a + d

Слайд 30Sum of an AP Example 6
Solving [1] and [3] gives

two solutions:
a = 8 and d = –3
a =

2 and d = 3

Substituting either of these pairs into a, a + d and a + 2d gives the same 3 numbers.
Therefore the three numbers in AP are 2, 5 and 8.
Sum of an AP Example 6Solving [1] and [3] gives two solutions:a = 8 and d =

Слайд 31In summary
An arithmetic progression (AP) is a sequence where we

add or subtract the same amount from term to term.
The

nth term of an AP is: Tn = a + (n – 1)d
The sum of the first n terms of an AP is:


where a is the first term, d is the common difference and l is the last term.


In summaryAn arithmetic progression (AP) is a sequence where we add or subtract the same amount from

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